Answer:
The area of the sumo wrestling ring is
![5.29 \pi](https://img.qammunity.org/2020/formulas/mathematics/high-school/o2v48umkbaowecs6b5ylf6lwta67o1e9hc.png)
Explanation:
The circumference of the circular sumo wrestling ring is
, that means its radius
is:
![2\pi r=4.6\pi](https://img.qammunity.org/2020/formulas/mathematics/high-school/cdsd7y3d5fedzkxw7e1f64bq6kthwapvha.png)
![r=(4.6)/(2) =\boxed{2.3\:meters.}](https://img.qammunity.org/2020/formulas/mathematics/high-school/8vwdw68399u8121devngjvyce680d8x8ag.png)
Now once we have the radius
of the sumo wrestling ring we can find its area
by the following formula:
![A=\pi r^2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/j29wdsg40jbed167khn7fs44y2z9velxu7.png)
Putting in the value of
we get:
![A=\pi (2.3m)^2=\boxed{5.29\pi\:\:m^2}](https://img.qammunity.org/2020/formulas/mathematics/high-school/a43yccw0h2h0gndxxvpr5cogyuudelul28.png)
Therefore the area of the sumo wrestling ring is
![{5.29\pi\:\:m^2](https://img.qammunity.org/2020/formulas/mathematics/high-school/9hwsa7fs9jujo7fea26qr5av7si0bni29j.png)