Question

The average kinetic energy of 1 mole of a gas at -32 degrees Celsius is:

3.01 x 103 J

3.99 x 102 J

-3.99 x 102 J

3.80 x 103 J

Answer 1

Answer:
`3.01* 10^(3)J`

Step-by-step explanation:

Let
`T` be the temperature in kelvin.

Let
`KE` be the average kinetic energy.

Let
`n` be the number of moles.

Let
`R` be the universal gas constant.

As we know,

`KE=(3)/(2)nRT`

Given,

`n=1\\T=273-32=241K`

we know that
`R=8.314JK^(-1)mol^(-1)`

So,
`KE=(3)/(2) * 1* 8.314* 241=3005.5J`=
`3.01* 10^(3)J`