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There are four numbers of which the first three are in G.P and the last three are in A.P where common difference is 6. If the first number and the last number are equal , then find the numbers.​
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There are four numbers of which the first three are in G.P and the last three are in A.P where common difference is 6. If the first number and the last number are equal , then find the numbers.​

User Sasha Kozachuk
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Sorry for the messy working but this is the answer in the box. Comment if you have any questions. Sorry again for the mess. I basically used algebra to manipulate the equations for AP and GP
There are four numbers of which the first three are in G.P and the last three are-example-1
User Frank Henard
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