Question

A line contains the points (8,9) and (-12, -7). Using point-slope form, write the equation of the line that is parallel to the given

line and that passes through (-5, -15).
A) y-15= -5/4 (x-5)
B) y+15= -5/4 (x+5)
C) y+5= 4/5 (x+15)
D) y+15= 4/5 (x+5)

Answer 1

D. y+15 = 4/5(x+5)

Explanation:

A line contains the points (8,9) and (-12, -7).

(y2 - y1) = m(x2 - x1)

(9 - (-7))= m (8 -(-12))

16 = m*20

m = 16/20 = 4/5

Given line has slope m= 4/5.

Parallel line has the same slope m = 4/5.

Point-slope equation is (y - y1) = m(x - x1).

We have slope m = 4/5, and point (-5, -15).

So,

(y - (-15)) = 4/5(x - (-5))

y+15 = 4/5(x+5)