Question

From the well we take out a bucket of water with volume V=5 litres where aproximately the work done is A=450J.

How deep is the surface of the well's water?
For velocity take g=10m/s2​

Answer 1

9m

Step-by-step explanation:

Given parameters:

Volume of the water = 5liters;

Since density = 1g/cm³

1L = 1000cm³

5L = 5000cm³

So;

mass = density x volume = 1 x 5000 = 5000g ; 5kg

Work done = 450J

Acceleration due to gravity = 10m/s²

Unknown:

Depth of the well = ?

Solution:

To solve this problem;

Work done = mass x gravity x depth

450 = 5 x 10 x depth

depth = 9m