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A planar electromagnetic wave of frequency 8.5×1014Hz is propagating in a vacuum in the +y direction. At a certain point P and at a given instant, the electric field of the wave is given by E⃗ =(0.041V/m)z ^. What is the magnetic vector of the wave at the point P at that instant?

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Answer:


B = 1.37 * 10^(-10) T

Step-by-step explanation:

As we know that in electromagnetic waves the two fields will induce each other

So here we have


B = (E)/(c)

we have


E = 0.041 V/m


c = 3* 10^8 m/s

so we have


B = (0.041)/(3 * 10^8)


B = 1.37 * 10^(-10) T

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