Question

P+n=131p+3.26n=248.52

Answer 1

Solution:

p = 79

n = 52

Explanation:

Given equations:

A)
`p+n=131`

B)
`p+3.26n=248.52`

To solve for
`p` and
`n`

Naming the first equation as A and second as B.

Using elimination method to solve.

In order to eliminate
`p` we subtract equation A from B.

Subtracting A from B i.e [
`B-A`

(B)
`p+3.26n=248.52`

- (A)
`p+n=131`

We get,
`3.26n-n=248.52-131`

`2.26n=117.52`

Dividing both sides 2.26.

`(2.26n)/(2.26)=(117.52)/(2.26)`

∴
`n=52`

We can solve for
`p` by substituting
`n=52` in equation A.

`p+52=131`

Subtracting both sides by 52.

`p+52-52=131-52`

∴
`p=79`