Question

Find a numerical value of one trigonometric function of x for cos^2x+ 2sin x-2=0

Answer 1

c on edge

Explanation:

idk what the guy above was doing

Answer 2

x = 90°

Explanation:

We are given a trigonometric function of x from which we have to a solution for x.

The function is
`\cos^(2) x + 2\sin x - 2 = 0`

⇒
`1 - \sin^(2) x + 2\sin x - 2 = 0`

{Since we know the identity
`\sin^(2) \alpha + \cos^(2) \alpha = 1`}

⇒
`\sin^(2) x - 2 \sin x + 1 = 0`

⇒
`(\sin x - 1)^(2) = 0`

{Since we know the formula (a - b)² = a² - 2ab + b²}

⇒
`(\sin x  - 1) = 0`

⇒
`\sin x = 1 = \sin 90`

⇒ x = 90° (Answer)