Question

A scallop forces open its shell with an elastic material called abductin whose elastic modulus is about 2.5× 10% N/m2 . If this piece of abductin is 3.0 mm thick and has a cross sectional area of 0.50 cm2 , how much potential energy does it store when compressed 1.0 mm?

Answer 1

U= 4.1×10^{-3} J

Step-by-step explanation:

Given:

Young's modulus E= 2.5×10^5 N/m^2

thickness of material L_o =3.0 mm

Area A= 0.50 cm^2

ΔL= 1.0 cm

The potential energy is given by

U= 1/2FΔx

`F = (EA)/(Lo)\Delta L`

therefore

`U=(1)/(2)(EA)/(Lo)\Delta L^2`

now putting values we get

`U=(1)/(2)(2.5*10^5*0.5*10^(-4))/(3*10^(-3))\Delta (1*10^(-3))^2`

U= 4.1×10^{-3} J