Question

1. -10x+5y = 40 (1 point)

Ox-intercept is 5; y-intercept is -10.
Ox-intercept is 8; y-intercept is -4.
Ox-intercept is -10; y-intercept is 5.
Ox-intercept is -4; y-intercept is 8.
For question 2, find the x- and y-intercept of the line.
2. 5x + 4y = 80 (1 point)
x-intercept is 4; y-intercept is 5.
x-intercept is 20; y-intercept is 16.
O x-intercept is 5; y-intercept is 4.
Ox-intercept is 16; v-intercept is 20.

Answer 1

1. Ox-intercept is -4; y-intercept is 8.

2. Ox-intercept is 16; v-intercept is 20.

Explanation:

1. -10x + 5y = 40

Recall the equation of line in slope - intercept form :

y = mx + c , where m is the slope and c is the y - intercept

Writing the given equation in this form,we have:

-10x + 5y = 40

5y = 10x + 40

y = 10/5 x + 40/5

y = 2x + 8

comparing with y = mx +c , then y - intercept is 8 , the x - intercept is the point at which y = 0 , substituting y = 0 into the equation , we have

0 = 2x + 8

2x = -8

x = -8/2

x = -4

2. Following the same procedure:

y = -5x/4 + 20

y - intercept = 20

x - intercept = 16