Question

A 1.0-m long wire is carrying a certain amount of current. The wire is placed perpendicular to a magnetic field of strength.20 T. If the wire experiences a force of 0.60 N, what is themagnitude of the current moving through the wire?

A) 1A
B) 5A
C) 4A
D) 2A
E) 3A

Answer 1

Current, I = 3 A

Step-by-step explanation:

It is given that,

Length of the wire, l = 1 m

Magnetic field acting on the wire, B = 0.2 T

The magnetic force acting on the wire, F = 0.6 N

Let the current flowing through the wire is given by I. The magnetic force acting on an object in the uniform magnetic field is given by :

`F=ILB\ sin\theta`

Here,
`\theta=90^(\circ)`

`F=ILB`

`I=(F)/(LB)`

`I=(0.6\ N)/(1\ m* 0.2\ T)`

I = 3 A

So, the current flowing through the rod 3 A.