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What is the perimeter of the figure?

A. 68 1/2 yd
B. 68 5/14 yd
C. 67 1/2 yd
D. 67 5/14 yd

What is the perimeter of the figure? A. 68 1/2 yd B. 68 5/14 yd C. 67 1/2 yd D. 67 5/14 yd-example-1
User Imrhung
by
5.4k points

1 Answer

4 votes

Answer:

The perimeter of the figure is,
68 (1)/(2) yd

Explanation:

The perimeter of the figure is,


(10(1)/(3) + 24(1)/(4) + 15(2)/(3) + 18(1)/(4)) yd

=
((10+24+15+18)+ (\frac {1}{3} + \frac {2}{3} + \frac {1}{4} + \frac {1}{4})) yd

=
(67 + 1 + (1)/(2)) yd

=
68 (1)/(2) yd

We know that if there is a polygon with side lengths
a_(i) unit ∀

i = 1(1}n where n ∈ N - {1, 2}

then, it's perimeter is given by,


\sum_(i=1)^(n)a_(i) unit

User SanketS
by
5.2k points
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