Question

33. How many atoms are present in 49.3 L of gaseous carbon tetrachloride at STP.

Answer 1

1.32 x 10²⁴

Step-by-step explanation:

Given parameters:

Volume of carbon tetrachloride = 49.3L

Unknown:

Number of atoms at STP = ?

Solution:

To solve this problem;

At STP;

1 mole of a substance occupies 22.4L ;

So;

Let us find the number of moles;

22.4L = 1 mole

49.3L will give
`(49.3)/(22.4)` = 2.2mole

So;

1 mole of substance contains 6.02 x 10²³ atoms

2.2 mole of Carbon tetrachloride = 2.2 x 6.02 x 10²³ = 1.32 x 10²⁴