Question

The London Eye, which is a giant Ferris wheel, has a diameter of 135 m. It revolves at a constant rate and takes 30 minutes to complete one revolution. What is the linear velocity of a rider in a capsule that is located at the perimeter of the wheel?

Answer 1

0.24 m/s

Step-by-step explanation:

Linear velocity of a rider in a capsule that is located at the perimeter of the wheel = 0.2355 m/s

Explanation:

Diameter = 135 m

Radius, r = 0.5 x 135 = 67.5 m

It revolves at a constant rate and takes 30 minutes

Period, T = 30 minutes= 1800 s

Linear velocity, v = radius x angular velocity

v = 67.5 x 3.98 x 10⁻³ = 0.2355 m/s

Linear velocity of a rider in a capsule that is located at the perimeter of the wheel = 0.2355 m/s

Answer 2

Linear velocity of a rider in a capsule that is located at the perimeter of the wheel = 0.2355 m/s

Step-by-step explanation:

Diameter = 135 m

Radius, r = 0.5 x 135 = 67.5 m

It revolves at a constant rate and takes 30 minutes

Period, T = 30 minutes= 1800 s

`\texttt{Angular velocity, }\omega =(2\pi )/(T)=(2\pi )/(1800)=3.49* 10^(-3)rad/s`

Linear velocity, v = radius x angular velocity

v = 67.5 x 3.98 x 10⁻³ = 0.2355 m/s

Linear velocity of a rider in a capsule that is located at the perimeter of the wheel = 0.2355 m/s