Answer:
a) $11,940.52
b) $11,956.18
c) $11,966.81
d) $11,910.16
Step-by-step explanation:
Given:
Investment amount = $10,000
Time = 3 years
Interest rate = 6%
Now,
Amount =
![P*(1+(r)/(n))^(nt)](https://img.qammunity.org/2020/formulas/business/high-school/g9y7f3nam35yjkxj864vd9nll5yn6w9qyq.png)
A = total amount
P = principal or amount of money deposited,
r = annual interest rate
n = number of times compounded per year
t = time in years
Thus,
a) compounded semiannually
n = 2
![Amount = \$10,000*(1+(0.06)/(2))^(2*3)](https://img.qammunity.org/2020/formulas/business/high-school/q5k2tk6uexo9m46s8i490sjm9slhoyimgd.png)
Amount = $10000 × 1.03⁶
or
Amount = $11,940.52
b) compounded quarterly
n = 4
![Amount = \$10,000*(1+(0.06)/(4))^(4*3)](https://img.qammunity.org/2020/formulas/business/high-school/sf3p5kufe8hjrh5rntfi5yf657zsa2rapd.png)
Amount = $10000 × 1.015¹²
or
Amount = $11,956.18
c) compounded monthly
n = 12
![Amount = \$10,000*(1+(0.06)/(12))^(12*3)](https://img.qammunity.org/2020/formulas/business/high-school/y4an7b6qxavp13mdrzkkjdv9b0a9vpfvnc.png)
Amount = $10000 × 1.00536³⁶
or
Amount = $11,966.81
d) compounded continuously
n = 12
![Amount = \$10,000*(1+(0.06)/(1))^(1*3)](https://img.qammunity.org/2020/formulas/business/high-school/t3bkcjbh42s874asgiv64cq7anuynvje6h.png)
Amount = $10000 × 1.06³
or
Amount = $11,910.16