Question

The probability of winning a certain lottery is 1/77076 for people who play 908 times find the mean number of wins

A) 0.0011
B) 84.9
C) 0.0118
D) 0.000013

Answer 1

The mean is 0.0118 approximately. So option C is correct

Solution:

Given that , The probability of winning a certain lottery is
`(1)/(77076)` for people who play 908 times

We have to find the mean number of wins

`\text { The probability of winning a lottery }=(1)/(77076)`

Assume that a procedure yields a binomial distribution with a trial repeated n times.

Use the binomial probability formula to find the probability of x successes given the probability p of success on a single trial.

`n=908, \text { probability } \mathrm{p}=(1)/(77076)`

`\text { Then, binomial mean }=n * p`

`\begin{array}{l}{\mu=908 * (1)/(77076)} \\\\ {\mu=(908)/(77076)} \\\\ {\mu=0.01178}\end{array}`

Hence, the mean is 0.0118 approximately. So option C is correct.