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It is believed that 5% of all people requesting travel brochures for transatlantic cruises actually take the cruise within 1 year of the request. An experienced travel agent believes this is wrong. Of 100 people requesting one of these brochures, only 3 have taken the cruise within 1 year. We want to test the travel agent's theory with a hypothesis test. Calculate the p-value for this test.

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Answer:

The p-value for this test is 0.3576 using the travel’s agent theory with a hypothesis test.

Step-by-step explanation:

To calculate p-value for this test, we need a test statistic which can be obtained if we know the sample proportion.


\text { So, sample proportion, } \hat{p}=(x)/(n)


\text { Where } x=\text { the people who have taken cruise within } 1 \text { year }=3, \text { and } n=\text { sample size }=100


\text { Now, } \hat{p}=(3)/(100)=0.03


\text { Now test statistic, } z=\frac{\hat{p}-p}{\sqrt{(p(1-p))/(n)}}


Z=\frac{0.03-0.05}{\sqrt{(0.05(1-0.05))/(100)}}


z=-0.92


\text { Here, } \mathrm{p}=\text { hypothesis test }=0.05


\text { Therefore, p-value for this test }=2 * \text { NORMDIST(- } 0.92)


\text { p-value for this test }=2 P(z<-0.92)


\text { p-value for this test }=0.3576

Hence, the p-value for this test is 0.3576 using the travel’s agent theory with a hypothesis test.

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