Question

Please help me!!! I dont understand Physics at all!

A small two passenger airplane taxing to the runway at 4 m/s has a takeoff speed of almost 30 m/s or more than 65 mi/hr. Determine the minimum length of the runway for the plane to reach that speed if it only takes 15 seconds to reach that speed. Show your work.

Answer 1

Answer:255
`m`

Step-by-step explanation:

Let
`s` be the distance of runway.

Let
`u` be the initial velocity of aeroplane.

Let
`v` be the initial velocity of aeroplane.

Let
`t` be the time taken by Susan.

Given,

`u=4ms^(-1)`

`v=30ms^(-1)\\t=15sec`

From the given information we can assume that no additional forces are acting.So,the acceleration is constant.

The length of runway will be minimum if the aeroplane takes off in
`15` seconds.

As we know from the equations of motion,

`s=(u+v)/(2)* t`

So,
`s=((4+30))/(2)* 15=255m`

So,the minimum length of the runway required is
`255m`