Question

One piece of copper jewelry at 101°C has twice the mass of another piece, which is at 38.0°C. Both pieces are placed inside a calorimeter of negligible heat capacity. What is the final temperature inside the calorimeter (c of copper=0.387 j/g.k)?

Answer 1

80.0°C will be the final temperature inside the calorimeter.

Step-by-step explanation:

Heat lost by the pace of jewelry will be equal to heat gained by the another piece of the jewelry

`-Q_1=Q_2`

Mass of piece-1=
`m_1=2m`

Specific heat capacity of copper=
`c` = 0.387 J/g.K

Initial temperature of the iron =
`T_1=101^oC`

Final temperature =
`T_2`=T

`Q_1=m_1c_1* (T-T_1)`

Mass of piece-2=
`m_2=m`

Specific heat capacity of copper =
`c` = 0.387 J/g.K

Initial temperature of the water =
`T_3=38.0^oC`

Final temperature of water =
`T_2`=T

`Q_2=m_2c_2* (T-T_3)`

`-Q_1=Q_2` (conservation of energy)

`-(m_1c_1* (T-T_1))=m_2c_2* (T-T_3)`

On substituting all values:

`-(2mc* (T-101^oC))=mc* (T-38.0^oC)`

`T= 80.0^oC`

80.0°C will be the final temperature inside the calorimeter.