Question

One of the reactions that occurs in a blast furnace, in which iron ore is converted to cast iron, is Fe2O3 + 3CO → 2Fe + 3CO2 Suppose that 1.19 × 103 kg of Fe is obtained from a 1.90 × 103 kg sample of Fe2O3. Assuming that the reaction goes to completion, what is the percent purity of Fe2O3 in the original sample?

Answer 1

`89.55~\%~of~Fe_2O_3~in~the~sample`

Step-by-step explanation:

The first step in this reaction is the converstion from Kg of
`Fe` to grams of
`Fe_2O_3`.

`1.19x10^3~Kg~Fe~(1000g~Fe)/(1~Kg~Fe)~(1~mol~Fe)/(55.84~g~Fe)~(1~mol~Fe_2O_3)/(2~mol~Fe)~(159.68~g~Fe_2O_3)/(1~mol~Fe_2O_3)~(1~Kg~Fe_2O_3)/(1000~g~Fe_2O_3)`

`X~=~1.7x10^3~Kg~Fe_2O_3`

Then we can calculate the percentage of
`Fe_2O_3` in the sample:

`\%~Fe_2O_3~=~(1.7x10^3~Kg~Fe_2O_3)/(1.9x10^3~Kg~Sample)*100`

`89.55~\%~of~Fe_2O_3~in~the~sample`