77.9k views
2 votes
Suppose Mike has a dresser with 3 tan pants, 5 jeans, 2 black pants, and 3 gray pants. He also has 2 brown shoes, 3 black shoes, and 2 blue shoes. If he randomly chooses a pair of pants and shoes, what is the probability that both are black? Give your answer as an exact fraction and reduce the fraction as much as possible.

User Cremz
by
8.4k points

1 Answer

4 votes

Answer:

Probability of choosing a black pair of pants and shoes
= (6)/(91)

Explanation:

Given:

Total number of pants Mike has =
\textrm{ 3 tan pants + 5 jeans + 2 black pants + 3 gray pants = 13 pair of pants}

Probability of randomly choosing a pair of black pants =
\frac{\textrm{Number of Black pants}}{\textrm{Total number of pants}} = (2)/(13)

Total number of shoes Mike has =
\textrm{ 2 brown shoes + 3 black shoes + 2 blue shoes = 7 pairs of shoes}

Probability of randomly choosing a pair of black shoes =
\frac{\textrm{Number of Black shoes}}{\textrm{Total number of shoes}} = (3)/(7)

Probability of choosing a black pair of pants and shoes =
(2)/(13)* (3)/(7) = (6)/(91)

User Cleankod
by
9.0k points