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Two boxes (24 kg and 62 kg) are being pushed across a horizontal frictionless surface, as the drawing shows. The 36-N pushing force ModifyingAbove Upper P With right-arrow is horizontal and is applied to the 24-kg box, which in turn pushes against the 62-kg box. Find the magnitude of the force ModifyingAbove Upper F With right-arrow that the 24-kg box applies to the 62-kg box.

User Veote
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1 Answer

1 vote

Answer:


F = 26.04 N

Step-by-step explanation:

As we know that system of two boxes are moving on frictionless surface

So here if two boxes are considered as a system

then we have


F = (m_1 + m_2) a


m_1 = 24 kg


m_2 = 62 kg


F = 36 N


36 = (24 + 62) a


a = 0.42 m/s^2

Now since we know that both the boxes are moving together so force applied by first box on other box is given as


F = ma


F = (62 * 0.42)


F = 26.04 N

User James Mulholland
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