Question

Calculate the specific heat of a piece of wood if 1500 grams of the wood absorbs

67,500 Joules of heat and its temperature changes from 32 °C to 57 °C.
0.18 J/g °C
1.2 J/g °C
1.8 J/g °C
0.48 J/g °C

Answer 1

Specific heat capacity of wood = 1.8 j/g. °C

Step-by-step explanation:

Given data:

Mass of wood = 1500 g

Heat absorbed = 67500 j

Initial temperature = 32 °C

Final temperature = 57 °C

Specific heat capacity = ?

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 57 - 32°C = 25°C

Q = m.c. ΔT

67500 j = 1500 g × c × 25°C

67500 j = 37500 g. °C × c

67500 j / 37500 g. °C = c

c = 1.8 j/g. °C

Specific heat capacity of wood is 1.8 j/g. °C.