Answer:
Surface area of Tetrahedron is 62.4 square units.
Note:(This is for only one surface of Tetrahedron)
Explanation:
Given :
The shape is Tetrahedron.
length of Base = 12 unit.
length of Height = 10.4 unit
To Find :
Surface area of Tetrahedron = ?
Solution:
Tetrahedron:
It is a polyhedron composed of
4 Triangular faces, ( four triangular surface)
6 Straight edges, and
4 Vertex corners.
Base Shape: Triangle
Side Shape: Triangle
We need to find surface area of Tetrahedron

Therefore, one side surface area of Tetrahedron is 62.4 square units.
If we required total surface area of the Tetrahedron then it will be multiplied by four, because it has 4 surface or 4 face.
Total surface area of Tetrahedron = 4 × 62.4
= 249.6 square units