Question

A submarine travels 7 km due East from its base and then turns and travels due North for 12.5

How far away is the submarine from its base?
Give your answer rounded to 1 DP.

Answer 1

The submarine is 10.4 km far from its base.

Explanation:

Given that:

Distance traveled east = 7km

Distance traveled north = 12.5 km

This is will form a right triangle, where the distance from east to north is hypotenuse.

Here,

a = 7 , b = x and c = 12.5

Using Pythagorean theorem,

`a^2+b^2=c^2\\(7)^2+x^2=(12.5)^2\\49+x^2=156.25\\x^2=156.25-49\\x^2=107.25`

Taking square root on both sides

`√(x^2)=√(107.25)\\x=10.4`

Hence,

The submarine is 10.4 km far from its base.