Question

Can somebody help me with the Math's questions on Pythagoras Theorem? Thanks

Answer 1

Part a)
`AB=17\ m`

Part b)
`AC=20.8\ m`

Explanation:

see the attached figure with letters to better understand the problem

Part a) Find the length AB

Applying the Pythagoras Theorem in the right triangle ABH

`AB^2=AH^2+HB^2`

where

AB is the hypotenuse (the greater side)

AH and HB are the legs of the right triangle

we have

`AH=FG=8\ m`

`HB=GB-ED=26-11=15\ m`

substitute the values

`AB^2=8^2+15^2`

`AB^2=289`

`AB=17\ m`

Part a) Find the length AC

Applying the Pythagoras Theorem in the right triangle ABC

`AC^2=AB^2+BC^2`

where

AC is the hypotenuse (the greater side)

AB and BC are the legs of the right triangle

we have

`BC=12\ m`

`AB=17\ m`

substitute

`AC^2=17^2+12^2`

`AC^2=433`

`AC=20.8\ m`