Question

Solve this pleasee!!!!!!!!!!!

Answer 1

1) Solution (2,-3)

2) Solution (-1,
`-(3)/(2)`)

3) Solution (
`\mathbf{-(1)/(2),-(5)/(2)}`)

Explanation:

We need to solve equations using elimination

1)
`2x+2y=-2\\3x-2y=12`

Let:

`2x+2y=-2--eq(1)\\3x-2y=12--eq(2)`

Adding both equations:

`2x+2y=-2\\3x-2y=12\\--------\\5x=10\\x=(10)/(5)\\x=2`

We get value of x = 2

Now, put value of x into equation 1 to find value of y

`2x+2y=-2\\Put\:x=2\\2(2)+2y=-2\\4+2y=-2\\2y=-2-4\\2y=-6\\y=-6/2\\y=-3`

So, we get y = -3

Solution (2,-3)

2)
`4x-2y=-1\\-4x+4y=-2`

Let:

`4x-2y=-1--eq(1)\\-4x+4y=-2--eq(2)`

Adding both equations

`4x-2y=-1\\-4x+4y=-2\\------\\2y=-3\\y=(-3)/(2)`

We get: y= -3/2

Now find value of x by putting value of y in eq(1)

`4x-2y=-1\\Put\:y=(-3)/(2)\\4x-2( (-3)/(2))=-1\\4x+3=-1\\4x=-1-3\\4x=-4\\x=(-4)/(4)\\x=-1`

We get x = -1

Solution (-1,
`-(3)/(2)`)

3)
`x-y=2\\x+y=-3`

let:

`x-y=2--eq(1)\\x+y=-3--eq(2)`

Add both equations:

`x-y=2\\x+y=-3\\-----\\2x=-1\\x=-(1)/(2)`

We get x = -1/2

Now, put value of x in equation 2

`x+y=-3\\-(1)/(2)+y=-3\\y=-3+ (1)/(2)\\y=(-6+1)/(2)\\y=(-5)/(2)`

We get y = -5/2

Solution (
`\mathbf{-(1)/(2),-(5)/(2)}`)