Question

A cat is moving at 18 m/s when it accelerates at 4 m/s2 for 2 seconds. What is his

new velocity? (Show which kinematic equation you used, along with your
answer)

Answer 1

26m/s

Step-by-step explanation:

Given parameters:

Initial velocity = 18m/s

Time = 2s

Acceleration = 4m/s²

Unknown:

Final velocity

Solution:

To solve this problem, we use the expression below:

Acceleration =
`(v - u )/(t)`

v is the final velocity

u is the initial velocity

t is the time taken

4 =
`(v - 18)/(2)`

v - 18 = 8

v = 8 + 18 = 26m/s