Question

A car of mass 1000kg goes on a circular track with a diameter of 100m. The car moves at constant speed and makes 6 revolutions in 2 min.

The frequency is Hz

The period of the car is s

The speed of the car is m/s

Answer 1

Answer:
`(1)/(20)`
`seconds^(-1)`,20
`seconds`,15.7
`ms^(-1)`

Step-by-step explanation:

Frequency is defined as the number of revolutions made the object in unit time.

Given that it takes
`2` minutes
`6` revolutions.

So,
`(6)/(2) =3` revolutions can be completed in
`1` minute.

So,
`(3)/(60) =(1)/(20)` revolutions can be completed in a second.

So,frequency is
`(1)/(20)`

Period of a object is the inverse of frequency.

Inverse of frequency
`(1)/((1)/(20) )=20`

So,period is
`20seconds`.

Speed of car is the given by the ratio of distance covered in one revolution to the time period.

Distance travelled in one period is
`\pi d` where
`d` is the diameter.

Given that
`d=100m`

So,distance travelled in one revolution
`\pi * 100=315.15m`

Time period is
`20seconds`.

Speed is
`(314.15)/(20)=15.7ms^(-1)`