Question

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If you have a 92.3 gram sample of silver that releases 1000.0 J energy, what is the temperature change of the water in a calorimeter if the specific heat of silver is 0.240 J/(goC)?

Answer 1

45.1°C

Step-by-step explanation:

Given parameters:

Mass of the silver = 92.3g

Quantity of energy released = 1000J

Specific heat of silver = 0.24J/g°C

Unknown:

Temperature change of the water = ?

Solution:

To solve this problem, we use the expression below:

H = m c Ф

H is the quantity of heat

m is the mass

c is the specific heat capacity

Ф is the temperature change

Insert the parameters and solve;

1000 = 92.3 x 0.24 x Ф

1000 = 22.15Ф

Ф = 45.1°C