Question

Which value of x is a solution...​

Answer 1

(4), -5/6

Explanation:

`13-36x^2-13=-12-13\\-36x^2=-25\\(-36x^2)/(-36)=(-25)/(-36)\\x^2=(25)/(36)\\x=\sqrt{(25)/(36)},\:x=-\sqrt{(25)/(36)}`For x^2 = f(a), x = f(a), -f(a)

`x=\sqrt{(25)/(36)},\:x=-\sqrt{(25)/(36)}\\\sqrt{(25)/(36)}\\√(25)\\√(5^2)=5\\=(5)/(√(36))\\√(36)\\=√(6^2)=6\\=(5)/(6)`

Reverse the same equation from the negative side

`=-(√(25))/(√(36))\\√(25)\\=√(5^2)\\=5\\=-(5)/(√(36))\\√(36)\\=√(6^2)\\=6\\=-(5)/(6)`

Therefore,

`x=\pm(5)/(6)`