Question

Tasha rolls a 7.0 bowling ball down down the alley for the league championship. One pin is still standing, and Jeanne hits it head-on with a velocity of 9.0 m/s . The 2.0pin acquires a forward velocity of 14.0m/s. . What is the new velocity of the bowling ball

Answer 1

Answer:5
`ms^(-1)`

Step-by-step explanation:

Let
`u_(1)` be the velocity of the bowling ball before collision.

Let
`u_(2)` be the velocity of the pin before collision.

Let
`v_(1)` be the velocity of the bowling ball after collision.

Let
`v_(2)` be the velocity of the pin after collision.

Let
`m_(1)` be the mass of the bowling ball.

Let
`m_(2)` be the mass of the pin.

According to the conservation of momentum,

`m_(1)u_(1)+m_(2)u_(2)=m_(1)v_(1)+m_(2)v_(2)`

Given,

`m_(1)=7Kg\\m_(2)=2Kg\\u_(1)=9ms^(-1)\\u_(2)=0ms^(-1)\\v_(2)=14ms^(-1)`

`7(9)+2(0)=7(v_(1))+2(14)`

`7v_(1)=35\\v_(1)=5ms^(-1)`

New velocity of bowling ball is
`5ms^(-1)`