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can anyone solve this step by step its 3x-2y=5 3x+y=8 in substitution please they are both the same problem​

User Molasses
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1 Answer

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3x-2y=5

3x+y=8

Rewrite the second equation as y = -3x +8

Substitute that into the first equation for y:

3x-2(-3x+8) = 5

Use distributive property:

3x +6x -16 = 5

Combine like terms:

9x - 16 = 5

Add 16 to both sides:

9x = 21

Divide both sides by 9:

x = 21/9

x = 7/3

Replace X in the first equation and solve for y:

3(7/3) -2y = 5

7 - 2y = 5

Subtract 7 from both sides:

-2y = -2

Divide both sides by -2:

y = 1

The solution is (7/3, 1)

User Pedroinpeace
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