Answer:
(0,1) and (-2,9)
Explanation:
A point (x,y) lies on the graph of f(x) =
if it satisfies the condition y =
![((1)/(3) )^(x)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/r5f0ou1fm3gvsn7bho466oj04duyc6dpkb.png)
(0,1):
x = 0 and y = 1.
This point satisfies the required condition as
= 1
Hence, this point is on the graph of f(x) =
![((1)/(3) )^(x)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/r5f0ou1fm3gvsn7bho466oj04duyc6dpkb.png)
(3,27):
x = 3 and y = 27.
This point doesn't satisfy the required condition as
=
≠ 27
Hence, this point is not on the graph of f(x) =
![((1)/(3) )^(x)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/r5f0ou1fm3gvsn7bho466oj04duyc6dpkb.png)
(-2,9):
x = -2 and y = 9.
This point satisfies the required condition as
=
= 9
Hence, this point is on the graph of f(x) =
![((1)/(3) )^(x)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/r5f0ou1fm3gvsn7bho466oj04duyc6dpkb.png)
(-1,
):
x = -1 and y =
.
This point satisfies the required condition as
y =
=
= 3 ≠
![-(1)/(3)](https://img.qammunity.org/2020/formulas/mathematics/high-school/zht2p3lnkpbftx1y1a74rvw916zop8zdm4.png)
Hence, this point is not on the graph of f(x) =
![((1)/(3) )^(x)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/r5f0ou1fm3gvsn7bho466oj04duyc6dpkb.png)