Question

What is the value of the range of the function f(x)=x²+2 for the domain value ¼?

A. y=2
B. y=2¼
C. y=2⅛
D. y=2 1/16​

Answer 1

D. For domain x =1/4 ,
`y =  2(1)/(16)`

Explanation:

Here, the given function is
`f(x) = x^2 + 2`

or we can also say that
`y= x^2 + 2`

Now, for domain value of x = 1/4

`y((1)/(4) ) = ((1)/(4) )^2 + 2 =  2 + (1)/(16 )  = 2(1)/(16)`

Hence, for domain x =1/4 ,
`y =  2(1)/(16)`