Question

A- 1000 m/s2
Xi-0m
Xf-0.75m
Vf-?

Answer 1

The final velocity of the object is,
`v_(f)` = 27 m/s

Step-by-step explanation:

Given,

The acceleration of the object, a = 1000 m/s²

The initial displacement of the object,
`x_(i)` = 0 m

The final displacement of the object,
`x_(f)` = 0.75 m

The initial velocity of the object will be,
`v_(i)` = o m/s

The final velocity of the object,
`v_(f)` = ?

The average velocity of the object,

v = (
`x_(f)` -
`x_(i)` )/ t

= 0.75 / t

The acceleration is given by the relation

a = v / t

1000 m/s² = 0.75 / t²

t² = 7.5 x 10⁻⁴

t = 0.027 s

Using the I equation of motion,

`v_(f)` = u + at

Substituting the values

`v_(f)` = 0 + 1000 x 0.027

= 27 m/s

Hence, the final velocity of the object is,
`v_(f)` = 27 m/s