Question

A hammer slides down a roof that makes a 30.0°angle with the horizontal. What are the magnitudes of the components of the hammer's velocity at the edge of the roof if it is moving at a speed of 8.25 m/s

Answer 1

Answer:7.14
`ms^(-1)`,4.125
`ms^(-1)`

Step-by-step explanation:

Whenever an object is moving in a 2D frame,its motion can be analysed as if it is travelling in two independent 1D frames.

One of such independent 1D frames are along horizontal and another along vertical.

Let
`v` be the total velocity.

Given that,
`v=8.25ms^(-1)`

We call the horizontal velocity as
`v_(h)` and the vertical velocity as
`v_(v)`.

`v_(h)`=
`vCos\alpha`

`v_(v)=vSin\alpha`

where
`\alpha` is the angle between the object and horizontal.

It is given that
`\alpha =30^(0)`

`v_(h)=8.25* Cos(30^(0))=7.14ms^(-1)`

`v_(v)=8.25* Sin(30^(0))=4.125ms^(-1)`