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The Atmospheric Pressure At This Altitude Is 461 MmHg. Assuming That The Atmosphere Is 18% Oxygen (by Volume), Calculate The Partial Pressure Of O2.

User Michelli
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Answer:

The partial pressure of the oxygen is 82.98 mmHg.

Step-by-step explanation:

From the given,

Atmospheric pressure = 461 mmHg

Atmospheric oxygen = 18%

Partial pressure of oxygen =?


Partial\,pressure\,of\,oxygen\,=\,Total\,pressure*Volume\,fraction


=$\text{461\,mmHg}$* (18)/(100)\,=82.98\,$\text{mmHg}$

Therefore, Partial pressure of oxygen is 82.98 mmHg.

User Ericlee
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