Question

The Atmospheric Pressure At This Altitude Is 461 MmHg. Assuming That The Atmosphere Is 18% Oxygen (by Volume), Calculate The Partial Pressure Of O2.

Answer 1

The partial pressure of the oxygen is 82.98 mmHg.

Step-by-step explanation:

From the given,

Atmospheric pressure = 461 mmHg

Atmospheric oxygen = 18%

Partial pressure of oxygen =?

`Partial\,pressure\,of\,oxygen\,=\,Total\,pressure*Volume\,fraction`

`=$\text{461\,mmHg}$* (18)/(100)\,=82.98\,$\text{mmHg}$`

Therefore, Partial pressure of oxygen is 82.98 mmHg.