Question

(-8,-2) and (-4,6) write a equation

Answer 1

The equation of line passing through (-8, -2) and (-4, 6) is y = 2x + 14

Solution:

Given that

Line is passing through point (− 8 ,− 2) and ( -4 , 6 )

Equation of line passing through point
`\left(x_(1), y_(1)\right) \text { and }\left(x_(2), y_(2)\right)` is given by:

`y-y_(1)=(\left(y_(2)-y_(1)\right))/(\left(x_(2)-x_(1)\right))\left(x-x_(1)\right)` ----- eqn 1

`\text { In our case } x_(1)=-8, y_(1)=-2, x_(2)=-4, y_(2)=6`

Substituting given value in (1) we get

`\begin{array}{l}{y-(-2)=((6-(-2)))/((-4-(-8)))(x-(-8))} \\\\ {=>y+2=(8)/(4)(x+8)} \\\\ {=>y+2=2(x+8)} \\\\ {=>y+2=2 x+16} \\\\ {=>-2 x+y=14}\end{array}`

Thus the required equation of line is y = 2x + 14