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What is the length of the mid segment of this trapezoid a(-11,3), b(0,3), d(-8,-2), and c(-1,-2)

? Units

User Paul King
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1 Answer

4 votes

Answer:

9 units.

Explanation:

Let ab and cd are the parallel sides of the given parallelogram.

Hence
(1)/(2) (ab + cd) is the mid segment of this trapezoid.

Now, coordinates of a, b, c and d are respectively (-11,3), (0,3), (-8,-2), and (-1,-2).

So, the length of ab =
\sqrt{(-11 - 0)^(2) + (3 - 3)^(2)} = 11 units

And the length of cd =
\sqrt{(-8 - (- 1))^(2) + (- 2 - ( - 2))^(2)  } = 7 units

Therefore, the mid segment of this trapezoid is
(1)/(2) (11 + 7) = 9 units. (Answer)

The length of a straight line connecting two points (
x_(1), y_(1)) and (
x_(2), y_(2)) is equal to


\sqrt{(x_(1) - x_(2))^(2) + (y_(1) - y_(2))^(2) }

User Xiaodong
by
6.7k points