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Which of the following is the probability against a spinner landing on a green section if the spinner has 15 sections and 3 of them are green?

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5 votes

Answer:


(1)/(5)

Explanation:

The probability of an event , E, happening is:

P(E) = Number of E/ Total Number

Here, we are considering a spinner with sections in color. We want probability that spinner lands on green. So we will need:

Number of divisions of spinner that is green, and

Number of total divisions in the spinner

We will then divide.

Now, from the problem, we are told that there are a total of 15 divisions. And out of those 15, three of them are green, thus:

Number of divisions that are green = 3

Total number of divisions = 15

Thus, the probability would be [let "G" be the event that spinner lands on green]:

P(G) =
(3)/(15)=(1)/(5)

This is the probability.

User Michael Commons
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