Answer:
,
,
,

Explanation:
see the attached figure with letters to better understand the problem
step 1
Find the value of b
In the right triangle BCD


Remember that

so


step 2
Find the value of d
In the right triangle BCD


Remember that

so


step 3
Find the value of a
In the right triangle ABD


Remember that


so


step 4
Find the value of c
In the right triangle ABD


Remember that


substitute


therefore



