Question

In ΔQRS, the measure of ∠S=90°, the measure of ∠R=69°, and QR = 19 feet. Find the length of RS to the nearest tenth of a foot. Answer quickly please.

Answer 1

Answer:7 feet

Explanation:

Since in a right angled triangle,

For an angle
`\alpha`,
`opposite=(Sin\alpha )hypotenuse`

`adjacent=(Cos\alpha )hypotenuse`

In the given triangle,

For the angle R,

`adjacent=RS`

`hypotenuse=QR`

Since
`adjacent=(Cos\alpha )hypotenuse`

`RS=Cos(69^(0))* 19=0.36* 19=6.8feet`

So,
`RS` is approximately
`7` feet.