Question

A body of mass 2 kilograms moves on a circle of radius 3 meters, making one revolution every 5 seconds. Find the magnitude of the centripetal force acting on the body. (Be sure to correctly state the units of the force.

Answer 1

Answer:
`F_c=9.375 N`

Step-by-step explanation:

Given

mass of body
`m=2 kg`

radius of circle
`r=3 m`

Time Period
`T=5 s`

suppose
`\omega`is the angular velocity of revolution

therefore
`\omega T=2\pi`

`\omega =(2\pi )/(5)=1.25 rad/s`

Centripetal acceleration
`a_c=\omega ^r`

`a_c=1.25^2* 3`

`a_c=4.68 m/s^2`

therefore centripetal
`F_c=m\omega ^2* r`

`F_c=9.375 N`