Question

The length of Sally's garden is 4 meters greater than 3 times the width.The perimeter of her garden is 72 meters.Find the dimensions of Sally's gardens

Answer 1

Width of the garden is 8m

Explanation:

Let width of garden = W while length of garden = L

From the question, we deduce the following:

Length L= 4+3W

Perimeter P = 72, (Recall that P = 2 (L+W))

72 = 2 (L+W)

72 = 2 ((4+3W)+W) ...... dividing both sides by 2,

36 = 4+3W+W

36 = 4+4W

36 - 4 = 4W

32 = 4W..... dividing both sides by 4,

W = 8m

Answer 2

The length is 28 meters

The width is 8 meters

Explanation:

Let x = the length of Sally's garden

Let Y= the width of Sally's garden.

The length of Sally's garden is 4 meters greater than 3 times the width. This means that the length is 3× the width + 4 meters. The equation is

x = 3y + 4

The perimeter of her garden is 72 meters. Since the length and the width are not equal, the garden is a rectangle.

Perimeter of rectangle = 2(length + width). Therefore,

2x + 2y = 72 - - - - - - - - - - -1

Substituting x = 3y + 4 into equation 1, it becomes .

2(3y + 4) + 2y = 72

6y + 8 + 2y = 72

6y + 2y = 72 - 8

8y = 64

y = 64/8 = 8

x = 3y + 4

x = 3×8 + 4 = 24 +4

x = 28