Question

A buffer can be prepared by mixing two solutions. Determine if each of the following mixtures will result in a buffer solution or not.1) Mixing 100.0 mL of 0.1 M HF with 100.0 mL of 0.05 M mol KF [ Select ] ["Yes, it will result in a buffer solution.", "No, it will not result in a buffer solution."] 2) Mixing 100.0 mL of 0.1 M NH3 with 100.0 mL of 0.1 M NH4Br [ Select ] ["Yes, it will result in a buffer solution.", "No, it will not result in a buffer solution."] 3) Mixing 100.0 mL of 0.1 M HCN with 100.0 mL of 0.05 M KOH [ Select ] ["No, it will not result in a buffer solution.", "Yes, it will result in a buffer solution."] 4) Mixing 100.0 mL of 0.1 M HCl with 100.0 mL of 0.1 M KCl [ Select ] ["Yes, it will result in a buffer solution.", "No, it will not result in a buffer solution."] 5) Mixing 100.0 mL of 0.1 M HCN with 100.0 mL of 0.1 M KOH [ Select ] ["Yes, it will result in a buffer solution.", "No, it will not result in a buffer solution."]

Answer 1

The answers are in the explanation

Step-by-step explanation:

A buffer is the mixture of a weak acid with its conjugate base or vice versa. Thus:

1) Mixing 100.0 mL of 0.1 M HF with 100.0 mL of 0.05 M mol KF. Will result in a buffer because HF is a weak acid and KF is its conjugate base.

2) Mixing 100.0 mL of 0.1 M NH₃ with 100.0 mL of 0.1 M NH₄Br. Will not result in a buffer because NH₃ is a strong base.

3) Mixing 100.0 mL of 0.1 M HCN with 100.0 mL of 0.05 M KOH. Will result in a buffer because HCN is a weak acid and its reaction with KOH will produce CN⁻ that is its conjugate base.

4) Mixing 100.0 mL of 0.1 M HCl with 100.0 mL of 0.1 M KCl Will not result in a buffer because HCl is a strong acid.

5) Mixing 100.0 mL of 0.1 M HCN with 100.0 mL of 0.1 M KOH Will not result in a buffer because each HCN will react with KOH producing CN⁻, that means that you will have just CN⁻ (Conjugate base) without HCN (Weak acid).

I hope it helps!