Question

A 69 g particle is moving to the left at 25 m/s . How much net work must be done on the particle to cause it to move to the right at 31 m/s ? Express your answer to two significant figures and include the appropriate units.

Answer 1

Answer:11.59 J

Step-by-step explanation:

Given

mass of Particle
`m=69 gm`

Initially Particle moves towards left
`v_1=25 m/s`

Final velocity of Particle is towards Right
`v_2=31 m/s`

According to Work Energy theorem

Work done by all the Forces=change in Kinetic Energy

Work done by Force
`=(mv_2^2)/(2)-(mv_1^2)/(2)`

`W=(69* 10^(-3))/(2)\left [ 31^-25^2\right ]`

`W=(69* 10^(-3))/(2)\left [ 961-625\right ]`

`W=11.59 J`