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A mass on a spring oscillates with a certain amplitude and a certain period T. If the mass is doubled, the spring constant of the spring is doubled, and the amplitude of motion is doubled, the period:

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Answer:

The period stays the same.

Step-by-step explanation:

The period "T" of a oscilating system composed by a amss on a spring is described by the following equation:


T=2\pi *\sqrt{(m)/(k)}

Where 'm' is the mass and 'k'is the spring constant.

From the equation, changes in amplitude don't interfere in the period. If both 'm' and 'k' are doubled:


T'= 2\pi *\sqrt{(2m)/(2k)}\\ T'= 2\pi *\sqrt{(m)/(k)}\\T' = T

The period stays the same.

User Abdul Ali
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