Question

WOULUJUTUL RECIPECUIUS.

Calculate the force between two objects that have masses of 20 kg and 100 kg separated
by a distance of 2.6 m.

Answer 1

The force between the two objects is 19.73 nN.

Explanation:

Any force acting between two objects tends to be directly proportional to the product of their masses and inversely proportional to the square of the distance between the two objects. And this kind of attraction force between two objects is termed as gravitational force.

So if we consider
`M_(1)` and
`M_(2)` as the masses of both objects and let d be the distance of separation of two objects. Then the force between the two objects can be determined as below:

`\text {Gravitational force}=(G * M_(1) * M_(2))/(d^(2))`

As gravitational constant
`G=6.67 * 10^(-11) \mathrm{m}^(3) \mathrm{kg}^(-1) \mathrm{s}^(-2)`,
`M_(1)` = 20 kg and
`M_(2)` = 100 kg, while d = 2.6 m, then

`\text {Gravitational force}=(6.67 * 10^(-11) * 20 * 100)/((2.6)^(2))=(6.67 * 20 * 10^(-9))/(6.76)`

Thus, we get finally,

`\text {Gravitational force}=19.73 * 10^(-9) \mathrm{N}`

As we know, nano denoted by letter 'n' equals to
`10^(-9)`

So the force acting between two objects is 19.73 nN.