Question

At the SuperSpeedy drive-through the time between consecutive customer arrivals has a mean of 50 seconds and a standard deviation of 30 seconds. There are two servers whose service time averages 80 seconds with a standard deviation of 20 seconds. Assume that no customers leave the drive-through after entry. a. What is the utilization of the employees?

Answer 1

utilization of employee is 80%

Explanation:

Given data:

mean = 50 sec

standard deviation is 30 sec

Average number of arrivals/ sec is

`\lambda = (1)/(50)`

service rate id 80 sec

`\mu =(1)/(80)`

The utilzation of employee is calculated as

`(\lambda)/(c\mu) = (80)/(2* 50) = 0.8`

i.e 80%

utilization of employee is 80%